(y+6)(16-4y)=0

Solution for (y+6)(16-4y)=0 equation:

(y+6)(16-4y)=0

We add all the numbers together, and all the variables

(y+6)(-4y+16)=0

We multiply parentheses ..

(-4y^2+16y-24y+96)=0

We get rid of parentheses

-4y^2+16y-24y+96=0

We add all the numbers together, and all the variables

-4y^2-8y+96=0

a = -4; b = -8; c = +96;
Δ = b2-4ac
Δ = -82-4·(-4)·96
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*-4}=\frac{-32}{-8}
=+4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*-4}=\frac{48}{-8}
=-6
$