(y+4/y+5)+1=y-3/y+3

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Solution for (y+4/y+5)+1=y-3/y+3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+4/y+1+5 = y-(3/y)+3 // - y-(3/y)+3

y-y+4/y+3/y-3+1+5 = 0

7*y^-1 = -3 // : 7

y^-1 = -3/7

-1 < 0

1/(y^1) = -3/7 // * y^1

1 = -3/7*y^1 // : -3/7

-7/3 = y^1

y = -7/3

y = -7/3

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