(y+4)(y+2)=0

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Solution for (y+4)(y+2)=0 equation:


Simplifying
(y + 4)(y + 2) = 0

Reorder the terms:
(4 + y)(y + 2) = 0

Reorder the terms:
(4 + y)(2 + y) = 0

Multiply (4 + y) * (2 + y)
(4(2 + y) + y(2 + y)) = 0
((2 * 4 + y * 4) + y(2 + y)) = 0
((8 + 4y) + y(2 + y)) = 0
(8 + 4y + (2 * y + y * y)) = 0
(8 + 4y + (2y + y2)) = 0

Combine like terms: 4y + 2y = 6y
(8 + 6y + y2) = 0

Solving
8 + 6y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + y)(2 + y) = 0

Subproblem 1

Set the factor '(4 + y)' equal to zero and attempt to solve: Simplifying 4 + y = 0 Solving 4 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + y = 0 + -4 y = 0 + -4 Combine like terms: 0 + -4 = -4 y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(2 + y)' equal to zero and attempt to solve: Simplifying 2 + y = 0 Solving 2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + y = 0 + -2 y = 0 + -2 Combine like terms: 0 + -2 = -2 y = -2 Simplifying y = -2

Solution

y = {-4, -2}

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