(y+4)(y+2)=

Solution for (y+4)(y+2)= equation:

Simplifying
(y + 4)(y + 2) = 0

Reorder the terms:
(4 + y)(y + 2) = 0

Reorder the terms:
(4 + y)(2 + y) = 0

Multiply (4 + y) * (2 + y)
(4(2 + y) + y(2 + y)) = 0
((2 * 4 + y * 4) + y(2 + y)) = 0
((8 + 4y) + y(2 + y)) = 0
(8 + 4y + (2 * y + y * y)) = 0
(8 + 4y + (2y + y2)) = 0

Combine like terms: 4y + 2y = 6y
(8 + 6y + y2) = 0

Solving
8 + 6y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + y)(2 + y) = 0

Subproblem 1
Set the factor '(4 + y)' equal to zero and attempt to solve:

Simplifying
4 + y = 0

Solving
4 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + y = 0 + -4
y = 0 + -4

Combine like terms: 0 + -4 = -4
y = -4

Simplifying
y = -4
Subproblem 2
Set the factor '(2 + y)' equal to zero and attempt to solve:

Simplifying
2 + y = 0

Solving
2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2
Solution
y = {-4, -2}