(y+3)/6=(y-2)/5

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Solution for (y+3)/6=(y-2)/5 equation: 



(y+3)/6=(y-2)/5

We move all terms to the left:

(y+3)/6-((y-2)/5)=0

We calculate fractions


y/()+(-((y-2)*6)/()=0



We calculate terms in parentheses: +(-((y-2)*6)/(), so:

-((y-2)*6)/(

We multiply all the terms by the denominator


-((y-2)*6)



We calculate terms in parentheses: -((y-2)*6), so:

(y-2)*6

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

-6y+12

Back to the equation:

+(-6y+12)



We get rid of parentheses

y/()-6y+12=0

We multiply all the terms by the denominator


y-6y*()+12*()=0

We add all the numbers together, and all the variables

y-6y*()=0

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