(y+29)40(2y)=180

Solution for (y+29)40(2y)=180 equation:

(y+29)40(2y)=180

We move all terms to the left:

(y+29)40(2y)-(180)=0

We multiply parentheses

402y^2+11658y-180=0

a = 402; b = 11658; c = -180;
Δ = b2-4ac
Δ = 116582-4·402·(-180)
Δ = 136198404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136198404}=\sqrt{36*3783289}=\sqrt{36}*\sqrt{3783289}=6\sqrt{3783289}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11658)-6\sqrt{3783289}}{2*402}=\frac{-11658-6\sqrt{3783289}}{804}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11658)+6\sqrt{3783289}}{2*402}=\frac{-11658+6\sqrt{3783289}}{804}
$