(y+2)2=9+2(2y+2)

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Solution for (y+2)2=9+2(2y+2) equation:



(y+2)2=9+2(2y+2)
We move all terms to the left:
(y+2)2-(9+2(2y+2))=0
We multiply parentheses
2y-(9+2(2y+2))+4=0
We calculate terms in parentheses: -(9+2(2y+2)), so:
9+2(2y+2)
determiningTheFunctionDomain 2(2y+2)+9
We multiply parentheses
4y+4+9
We add all the numbers together, and all the variables
4y+13
Back to the equation:
-(4y+13)
We get rid of parentheses
2y-4y-13+4=0
We add all the numbers together, and all the variables
-2y-9=0
We move all terms containing y to the left, all other terms to the right
-2y=9
y=9/-2
y=-4+1/2

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