(y+2)(16y+4)=0

Solution for (y+2)(16y+4)=0 equation:

(y+2)(16y+4)=0

We multiply parentheses ..

(+16y^2+4y+32y+8)=0

We get rid of parentheses

16y^2+4y+32y+8=0

We add all the numbers together, and all the variables

16y^2+36y+8=0

a = 16; b = 36; c = +8;
Δ = b2-4ac
Δ = 362-4·16·8
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-28}{2*16}=\frac{-64}{32}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+28}{2*16}=\frac{-8}{32}
=-1/4
$