(y+14)(y-1)=0

Solution for (y+14)(y-1)=0 equation:

(y+14)(y-1)=0

We multiply parentheses ..

(+y^2-1y+14y-14)=0

We get rid of parentheses

y^2-1y+14y-14=0

We add all the numbers together, and all the variables

y^2+13y-14=0

a = 1; b = 13; c = -14;
Δ = b2-4ac
Δ = 132-4·1·(-14)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*1}=\frac{-28}{2}
=-14
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*1}=\frac{2}{2}
=1
$