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(y+1)(y+6)=9
We move all terms to the left:
(y+1)(y+6)-(9)=0
We multiply parentheses ..
(+y^2+6y+y+6)-9=0
We get rid of parentheses
y^2+6y+y+6-9=0
We add all the numbers together, and all the variables
y^2+7y-3=0
a = 1; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·1·(-3)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{61}}{2*1}=\frac{-7-\sqrt{61}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{61}}{2*1}=\frac{-7+\sqrt{61}}{2} $
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