(y+1)(y+2)=0

Solution for (y+1)(y+2)=0 equation:

Simplifying
(y + 1)(y + 2) = 0

Reorder the terms:
(1 + y)(y + 2) = 0

Reorder the terms:
(1 + y)(2 + y) = 0

Multiply (1 + y) * (2 + y)
(1(2 + y) + y(2 + y)) = 0
((2 * 1 + y * 1) + y(2 + y)) = 0
((2 + 1y) + y(2 + y)) = 0
(2 + 1y + (2 * y + y * y)) = 0
(2 + 1y + (2y + y2)) = 0

Combine like terms: 1y + 2y = 3y
(2 + 3y + y2) = 0

Solving
2 + 3y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(2 + y)(1 + y) = 0

Subproblem 1
Set the factor '(2 + y)' equal to zero and attempt to solve:

Simplifying
2 + y = 0

Solving
2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2
Subproblem 2
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Solution
y = {-2, -1}