(x2-x)/7=(5x-5)/4

Solution for (x2-x)/7=(5x-5)/4 equation:

x in (-oo:+oo)

(x^2-x)/7 = (5*x-5)/4 // - (5*x-5)/4

(x^2-x)/7-((5*x-5)/4) = 0

(x^2-x)/7+(-1*(5*x-5))/4 = 0

(4*(x^2-x))/(4*7)+(-1*7*(5*x-5))/(4*7) = 0

4*(x^2-x)-1*7*(5*x-5) = 0

4*x^2-39*x+35 = 0

4*x^2-39*x+35 = 0

4*x^2-39*x+35 = 0

DELTA = (-39)^2-(4*4*35)

DELTA = 961

DELTA > 0

x = (961^(1/2)+39)/(2*4) or x = (39-961^(1/2))/(2*4)

x = 35/4 or x = 1

(x-1)*(x-35/4) = 0

((x-1)*(x-35/4))/(4*7) = 0

((x-1)*(x-35/4))/(4*7) = 0 // * 4*7

(x-1)*(x-35/4) = 0

( x-1 )

x-1 = 0 // + 1

x = 1

( x-35/4 )

x-35/4 = 0 // + 35/4

x = 35/4

x in { 1, 35/4 }