(x2)+(1.6)=12x

Solution for (x2)+(1.6)=12x equation:

(x2)+(1.6)=12x

We move all terms to the left:

(x2)+(1.6)-(12x)=0

We add all the numbers together, and all the variables

x^2-12x+1.6=0

a = 1; b = -12; c = +1.6;
Δ = b2-4ac
Δ = -122-4·1·1.6
Δ = 137.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{137.6}}{2*1}=\frac{12-\sqrt{137.6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{137.6}}{2*1}=\frac{12+\sqrt{137.6}}{2}
$