(x/x-2)-(1/x+3)=2

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Solution for (x/x-2)-(1/x+3)=2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/x-(1/x)-3-2 = 2 // - 2

x/x-(1/x)-3-2-2 = 0

x/x-x^-1-3-2-2 = 0

-1*x^-1 = 6 // : -1

x^-1 = -6

-1 < 0

1/(x^1) = -6 // * x^1

1 = -6*x^1 // : -6

-1/6 = x^1

x = -1/6

x = -1/6

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