(x/9)+(x/3)=(1/9)

Solution for (x/9)+(x/3)=(1/9) equation:

(x/9)+(x/3)=(1/9)

We move all terms to the left:

(x/9)+(x/3)-((1/9))=0

We add all the numbers together, and all the variables

(+x/9)+(+x/3)-((+1/9))=0

We get rid of parentheses

x/9+x/3-((+1/9))=0

We calculate fractions


729x^2/()+3x/()+()/()=0

We add all the numbers together, and all the variables

729x^2/()+3x/()+1=0

We multiply all the terms by the denominator


729x^2+3x+1*()=0

We add all the numbers together, and all the variables

729x^2+3x=0

a = 729; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·729·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*729}=\frac{-6}{1458}
=-1/243
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*729}=\frac{0}{1458}
=0
$