(x/5)-7=(9/10)

Solution for (x/5)-7=(9/10) equation:

(x/5)-7=(9/10)

We move all terms to the left:

(x/5)-7-((9/10))=0

We add all the numbers together, and all the variables

(+x/5)-7-((+9/10))=0

We get rid of parentheses

x/5-7-((+9/10))=0

We calculate fractions


10x^2/()-7+()/()=0

We add all the numbers together, and all the variables

10x^2/()-6=0

We multiply all the terms by the denominator


10x^2-6*()=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$