(x/5)+(x/7)=(7/10)

Solution for (x/5)+(x/7)=(7/10) equation:

(x/5)+(x/7)=(7/10)

We move all terms to the left:

(x/5)+(x/7)-((7/10))=0

We add all the numbers together, and all the variables

(+x/5)+(+x/7)-((+7/10))=0

We get rid of parentheses

x/5+x/7-((+7/10))=0

We calculate fractions


70x^2/()+50x^2/()+()/()=0

We add all the numbers together, and all the variables

70x^2/()+50x^2/()+1=0

We multiply all the terms by the denominator


70x^2+50x^2+1*()=0

We add all the numbers together, and all the variables

120x^2=0

a = 120; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·120·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{240}=0$