(x/4)+(x/9)=(13/36)

Solution for (x/4)+(x/9)=(13/36) equation:

(x/4)+(x/9)=(13/36)

We move all terms to the left:

(x/4)+(x/9)-((13/36))=0

We add all the numbers together, and all the variables

(+x/4)+(+x/9)-((+13/36))=0

We get rid of parentheses

x/4+x/9-((+13/36))=0

We calculate fractions


972x^2/()+432x^2/()+()/()=0

We add all the numbers together, and all the variables

972x^2/()+432x^2/()+1=0

We multiply all the terms by the denominator


972x^2+432x^2+1*()=0

We add all the numbers together, and all the variables

1404x^2=0

a = 1404; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1404·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2808}=0$