(x/4)+(x/7)=(7/8)

Solution for (x/4)+(x/7)=(7/8) equation:

(x/4)+(x/7)=(7/8)

We move all terms to the left:

(x/4)+(x/7)-((7/8))=0

We add all the numbers together, and all the variables

(+x/4)+(+x/7)-((+7/8))=0

We get rid of parentheses

x/4+x/7-((+7/8))=0

We calculate fractions


448x^2/()+256x^2/()+()/()=0

We add all the numbers together, and all the variables

448x^2/()+256x^2/()+1=0

We multiply all the terms by the denominator


448x^2+256x^2+1*()=0

We add all the numbers together, and all the variables

704x^2=0

a = 704; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·704·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{1408}=0$