(x/3+7)=3x/2-2(x-1)

Solution for (x/3+7)=3x/2-2(x-1) equation:

(x/3+7)=3x/2-2(x-1)

We move all terms to the left:

(x/3+7)-(3x/2-2(x-1))=0


Domain of the equation: 2-2(x-1))!=0

We move all terms containing x to the left, all other terms to the right

-2(x-1))!=-2

x∈R


We get rid of parentheses

x/3-(3x/2-2(x-1))+7=0

We calculate fractions


()/(-2(x-1))-(3x*3)/(-2(x-1))+7+3*2)+(+3*2)=0


We calculate terms in parentheses: +()/(-2(x-1)), so:

)/(-2(x-1)

We add all the numbers together, and all the variables

-2(x-1)+)/(

We multiply parentheses

-2x+2+)/(

We multiply all the terms by the denominator


-2x*(+2*(+)

We add all the numbers together, and all the variables

-2x*(+2*0

Back to the equation:

+(-2x*(+2*0)



We calculate terms in parentheses: -(3x*3)/(-2(x-1)), so:

3x*3)/(-2(x-1)

We multiply parentheses

3x*3)/(-2x+2

We multiply all the terms by the denominator


3x*3)-2x*(+2*(

We add all the numbers together, and all the variables

3x*3)-2x*(

Wy multiply elements

9x^3

We do not support expression: x^3