(x/3)+(3/x)=1

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Solution for (x/3)+(3/x)=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/3+3/x = 1 // - 1

x/3+3/x-1 = 0

1/3*x^1+3*x^-1-1*x^0 = 0

(1/3*x^2-1*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(1/3*x^2-1*x^1+3*x^0) = 0

x^1

(1/3)*x^2-x+3 = 0

(1/3)*x^2-x+3 = 0

DELTA = (-1)^2-(3*4*(1/3))

DELTA = -3

DELTA < 0

x in { } 

x belongs to the empty set

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