(x/2)-3=1(1/6)

Solution for (x/2)-3=1(1/6) equation:

(x/2)-3=1(1/6)

We move all terms to the left:

(x/2)-3-(1(1/6))=0

We add all the numbers together, and all the variables

(+x/2)-3-(1(+1/6))=0

We get rid of parentheses

x/2-3-(1(+1/6))=0

We calculate fractions


6x^2/()-3+()/()=0

We add all the numbers together, and all the variables

6x^2/()-2=0

We multiply all the terms by the denominator


6x^2-2*()=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$