(x/2)+(x/8)=(1/8)

Solution for (x/2)+(x/8)=(1/8) equation:

(x/2)+(x/8)=(1/8)

We move all terms to the left:

(x/2)+(x/8)-((1/8))=0

We add all the numbers together, and all the variables

(+x/2)+(+x/8)-((+1/8))=0

We get rid of parentheses

x/2+x/8-((+1/8))=0

We calculate fractions


512x^2/()+2x/()+()/()=0

We add all the numbers together, and all the variables

512x^2/()+2x/()+1=0

We multiply all the terms by the denominator


512x^2+2x+1*()=0

We add all the numbers together, and all the variables

512x^2+2x=0

a = 512; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·512·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*512}=\frac{-4}{1024}
=-1/256
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*512}=\frac{0}{1024}
=0
$