(x/(x+2))=6+(3/(x+2))

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Solution for (x/(x+2))=6+(3/(x+2)) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

x/(x+2) = 3/(x+2)+6 // - 3/(x+2)+6

x/(x+2)-(3/(x+2))-6 = 0

x/(x+2)-3*(x+2)^-1-6 = 0

x/(x+2)-3/(x+2)-6 = 0

x/(x+2)-3/(x+2)+(-6*(x+2))/(x+2) = 0

x-6*(x+2)-3 = 0

x-6*x-12-3 = 0

-5*x-15 = 0

(-5*x-15)/(x+2) = 0

(-5*x-15)/(x+2) = 0 // * x+2

-5*x-15 = 0

-5*x-15 = 0 // + 15

-5*x = 15 // : -5

x = 15/(-5)

x = -3

x = -3

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