(x.x.2)+10x+12=2(x+2)(x+3)

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Solution for (x.x.2)+10x+12=2(x+2)(x+3) equation: 



(x.x.2)+10x+12=2(x+2)(x+3)

We move all terms to the left:

(x.x.2)+10x+12-(2(x+2)(x+3))=0

We add all the numbers together, and all the variables

(+x.x.2)+10x-(2(x+2)(x+3))+12=0

We add all the numbers together, and all the variables

10x+(+x.x.2)-(2(x+2)(x+3))+12=0

We get rid of parentheses

10x+x.x.2-(2(x+2)(x+3))+12=0

We multiply parentheses ..

-(2(+x^2+3x+2x+6))+10x+x.x.2+12=0



We calculate terms in parentheses: -(2(+x^2+3x+2x+6)), so:

2(+x^2+3x+2x+6)

We multiply parentheses

2x^2+6x+4x+12

We add all the numbers together, and all the variables

2x^2+10x+12

Back to the equation:

-(2x^2+10x+12)



We add all the numbers together, and all the variables

10x-(2x^2+10x+12)+x.x.2+12=0

We get rid of parentheses

-2x^2+10x-10x+x.x.2-12+12=0

We add all the numbers together, and all the variables

-2x^2+x.x.2=0

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