(x-8)(9x)=0

Solution for (x-8)(9x)=0 equation:

(x-8)(9x)=0

We multiply parentheses

9x^2-72x=0

a = 9; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·9·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*9}=\frac{0}{18}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*9}=\frac{144}{18}
=8
$