(x-7)(x-5)+x(8-x)=-5

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Solution for (x-7)(x-5)+x(8-x)=-5 equation: 



(x-7)(x-5)+x(8-x)=-5

We move all terms to the left:

(x-7)(x-5)+x(8-x)-(-5)=0

We add all the numbers together, and all the variables

(x-7)(x-5)+x(-1x+8)-(-5)=0

We add all the numbers together, and all the variables

(x-7)(x-5)+x(-1x+8)+5=0

We multiply parentheses

-1x^2+(x-7)(x-5)+8x+5=0

We multiply parentheses ..

-1x^2+(+x^2-5x-7x+35)+8x+5=0

We get rid of parentheses

-1x^2+x^2-5x-7x+8x+35+5=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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