(x-6)+9+(2x-19)=22

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Solution for (x-6)+9+(2x-19)=22 equation: 



(x-6)+9+(2x-19)=22

We move all terms to the left:

(x-6)+9+(2x-19)-(22)=0

We add all the numbers together, and all the variables

(x-6)+(2x-19)-13=0

We get rid of parentheses

x+2x-6-19-13=0

We add all the numbers together, and all the variables

3x-38=0

We move all terms containing x to the left, all other terms to the right

3x=38

x=38/3

x=12+2/3

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