(x-6)(x-5)+(x+2)(x+2)=0

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Solution for (x-6)(x-5)+(x+2)(x+2)=0 equation:



(x-6)(x-5)+(x+2)(x+2)=0
We multiply parentheses ..
(+x^2-5x-6x+30)+(x+2)(x+2)=0
We get rid of parentheses
x^2-5x-6x+(x+2)(x+2)+30=0
We multiply parentheses ..
x^2+(+x^2+2x+2x+4)-5x-6x+30=0
We add all the numbers together, and all the variables
x^2+(+x^2+2x+2x+4)-11x+30=0
We get rid of parentheses
x^2+x^2+2x+2x-11x+4+30=0
We add all the numbers together, and all the variables
2x^2-7x+34=0
a = 2; b = -7; c = +34;
Δ = b2-4ac
Δ = -72-4·2·34
Δ = -223
Delta is less than zero, so there is no solution for the equation

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