(x-5)/2=(3x-7)/7

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Solution for (x-5)/2=(3x-7)/7 equation:



(x-5)/2=(3x-7)/7
We move all terms to the left:
(x-5)/2-((3x-7)/7)=0
We calculate fractions
x/()+(-((3x-7)*2)/()=0
We calculate terms in parentheses: +(-((3x-7)*2)/(), so:
-((3x-7)*2)/(
We multiply all the terms by the denominator
-((3x-7)*2)
We calculate terms in parentheses: -((3x-7)*2), so:
(3x-7)*2
We multiply parentheses
6x-14
Back to the equation:
-(6x-14)
We get rid of parentheses
-6x+14
Back to the equation:
+(-6x+14)
We get rid of parentheses
x/()-6x+14=0
We multiply all the terms by the denominator
x-6x*()+14*()=0
We add all the numbers together, and all the variables
x-6x*()=0

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