(x-5)+(4x+26)=(8x-30)

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Solution for (x-5)+(4x+26)=(8x-30) equation: 



(x-5)+(4x+26)=(8x-30)

We move all terms to the left:

(x-5)+(4x+26)-((8x-30))=0

We get rid of parentheses

x+4x-((8x-30))-5+26=0



We calculate terms in parentheses: -((8x-30)), so:

(8x-30)

We get rid of parentheses

8x-30

Back to the equation:

-(8x-30)



We add all the numbers together, and all the variables

5x-(8x-30)+21=0

We get rid of parentheses

5x-8x+30+21=0

We add all the numbers together, and all the variables

-3x+51=0

We move all terms containing x to the left, all other terms to the right

-3x=-51

x=-51/-3

x=+17

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