(x-5)(x-1)=(x-1)(x-2)

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Solution for (x-5)(x-1)=(x-1)(x-2) equation:



(x-5)(x-1)=(x-1)(x-2)
We move all terms to the left:
(x-5)(x-1)-((x-1)(x-2))=0
We multiply parentheses ..
(+x^2-1x-5x+5)-((x-1)(x-2))=0
We calculate terms in parentheses: -((x-1)(x-2)), so:
(x-1)(x-2)
We multiply parentheses ..
(+x^2-2x-1x+2)
We get rid of parentheses
x^2-2x-1x+2
We add all the numbers together, and all the variables
x^2-3x+2
Back to the equation:
-(x^2-3x+2)
We get rid of parentheses
x^2-x^2-1x-5x+3x+5-2=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1

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