(x-4/5x)=(1/5x)+1

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Solution for (x-4/5x)=(1/5x)+1 equation: 



(x-4/5x)=(1/5x)+1

We move all terms to the left:

(x-4/5x)-((1/5x)+1)=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5x)+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+x-4/5x)-((+1/5x)+1)=0

We get rid of parentheses

x-4/5x-((+1/5x)+1)=0

We calculate fractions


x+(-20x)/25x^2+(-((+1*5x)/25x^2=0

We multiply all the terms by the denominator


x*25x^2+(-20x)+(-((+1*5x)=0



We calculate terms in parentheses: +(-((+1*5x), so:

-((+1*5x



Wy multiply elements

25x^3+(-20x)+(-((+1*5x)=0

We get rid of parentheses

25x^3-20x+(-((+1*5x)=0



We calculate terms in parentheses: +(-((+1*5x), so:

-((+1*5x



We do not support expression: x^3

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