(x-4)=(x2-8x+16)

Solution for (x-4)=(x2-8x+16) equation:

(x-4)=(x2-8x+16)

We move all terms to the left:

(x-4)-((x2-8x+16))=0

We add all the numbers together, and all the variables

-((+x^2-8x+16))+(x-4)=0

We get rid of parentheses

-((+x^2-8x+16))+x-4=0


We calculate terms in parentheses: -((+x^2-8x+16)), so:

(+x^2-8x+16)

We get rid of parentheses

x^2-8x+16

Back to the equation:

-(x^2-8x+16)


We add all the numbers together, and all the variables

x-(x^2-8x+16)-4=0

We get rid of parentheses

-x^2+x+8x-16-4=0

We add all the numbers together, and all the variables

-1x^2+9x-20=0

a = -1; b = 9; c = -20;
Δ = b2-4ac
Δ = 92-4·(-1)·(-20)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*-1}=\frac{-10}{-2}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*-1}=\frac{-8}{-2}
=+4
$