(x-4)/35

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Solution for (x-4)/35 equation: 


x in (-oo:+oo)

(x-4)/3 < 5 // - 5

(x-4)/3-5 < 0

(x-4)/3+(-5*3)/3 < 0

x-5*3-4 < 0

x-19 < 0

(x-19)/3 < 0

(x-19)/3 < 0 // * 3^2

3*(x-19) < 0

( 3 )

3 < 0

x belongs to the empty set

( x-19 )

x-19 < 0 // + 19

x < 19

	(-oo:19)	(19:+oo)
3	+	+
x-19	-	+


x in (-oo:19)

(-oo:19)

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