(x-4)/3-(2x+1)/7=(5x-1)/2

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Solution for (x-4)/3-(2x+1)/7=(5x-1)/2 equation: 


x in (-oo:+oo)

(x-4)/3-((2*x+1)/7) = (5*x-1)/2 // - (5*x-1)/2

(x-4)/3-((2*x+1)/7)-((5*x-1)/2) = 0

(x-4)/3+(-1*(2*x+1))/7+(-1*(5*x-1))/2 = 0

(2*7*(x-4))/(2*3*7)+(-1*2*3*(2*x+1))/(2*3*7)+(-1*3*7*(5*x-1))/(2*3*7) = 0

2*7*(x-4)-1*2*3*(2*x+1)-1*3*7*(5*x-1) = 0

2*x-105*x-62+21 = 0

-103*x-41 = 0

(-103*x-41)/(2*3*7) = 0

(-103*x-41)/(2*3*7) = 0 // * 2*3*7

-103*x-41 = 0

-103*x-41 = 0 // + 41

-103*x = 41 // : -103

x = 41/(-103)

x = -41/103

x = -41/103

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