(x-4)/(-2)-(4x+5)/(2x+3)=0

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Solution for (x-4)/(-2)-(4x+5)/(2x+3)=0 equation: 



(x-4)/(-2)-(4x+5)/(2x+3)=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R



We calculate fractions


((x-4)*(2x+3))/((-2)*(2x+3))+(-(4x+5)*(-2))/((-2)*(2x+3))=0



We calculate terms in parentheses: +((x-4)*(2x+3))/((-2)*(2x+3)), so:

(x-4)*(2x+3))/((-2)*(2x+3)

We multiply all the terms by the denominator


(x-4)*(2x+3))

Back to the equation:

+((x-4)*(2x+3)))





We calculate terms in parentheses: +(-(4x+5)*(-2))/((-2)*(2x+3)), so:

-(4x+5)*(-2))/((-2)*(2x+3)

We multiply all the terms by the denominator


-(4x+5)*(-2))

Back to the equation:

+(-(4x+5)*(-2)))

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