(x-4)+6=2-(4-2x)

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Solution for (x-4)+6=2-(4-2x) equation:



(x-4)+6=2-(4-2x)
We move all terms to the left:
(x-4)+6-(2-(4-2x))=0
We add all the numbers together, and all the variables
(x-4)-(2-(-2x+4))+6=0
We get rid of parentheses
x-(2-(-2x+4))-4+6=0
We calculate terms in parentheses: -(2-(-2x+4)), so:
2-(-2x+4)
determiningTheFunctionDomain -(-2x+4)+2
We get rid of parentheses
2x-4+2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We add all the numbers together, and all the variables
x-(2x-2)+2=0
We get rid of parentheses
x-2x+2+2=0
We add all the numbers together, and all the variables
-1x+4=0
We move all terms containing x to the left, all other terms to the right
-x=-4
x=-4/-1
x=+4

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