(x-4)(x+3)=(x-6)(x-4)

Solution for (x-4)(x+3)=(x-6)(x-4) equation:

(x-4)(x+3)=(x-6)(x-4)

We move all terms to the left:

(x-4)(x+3)-((x-6)(x-4))=0

We multiply parentheses ..

(+x^2+3x-4x-12)-((x-6)(x-4))=0


We calculate terms in parentheses: -((x-6)(x-4)), so:

(x-6)(x-4)

We multiply parentheses ..

(+x^2-4x-6x+24)

We get rid of parentheses

x^2-4x-6x+24

We add all the numbers together, and all the variables

x^2-10x+24

Back to the equation:

-(x^2-10x+24)


We get rid of parentheses

x^2-x^2+3x-4x+10x-12-24=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4