(x-4)(x+2)=-4(x-4)

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Solution for (x-4)(x+2)=-4(x-4) equation:


Simplifying
(x + -4)(x + 2) = -4(x + -4)

Reorder the terms:
(-4 + x)(x + 2) = -4(x + -4)

Reorder the terms:
(-4 + x)(2 + x) = -4(x + -4)

Multiply (-4 + x) * (2 + x)
(-4(2 + x) + x(2 + x)) = -4(x + -4)
((2 * -4 + x * -4) + x(2 + x)) = -4(x + -4)
((-8 + -4x) + x(2 + x)) = -4(x + -4)
(-8 + -4x + (2 * x + x * x)) = -4(x + -4)
(-8 + -4x + (2x + x2)) = -4(x + -4)

Combine like terms: -4x + 2x = -2x
(-8 + -2x + x2) = -4(x + -4)

Reorder the terms:
-8 + -2x + x2 = -4(-4 + x)
-8 + -2x + x2 = (-4 * -4 + x * -4)
-8 + -2x + x2 = (16 + -4x)

Solving
-8 + -2x + x2 = 16 + -4x

Solving for variable 'x'.

Reorder the terms:
-8 + -16 + -2x + 4x + x2 = 16 + -4x + -16 + 4x

Combine like terms: -8 + -16 = -24
-24 + -2x + 4x + x2 = 16 + -4x + -16 + 4x

Combine like terms: -2x + 4x = 2x
-24 + 2x + x2 = 16 + -4x + -16 + 4x

Reorder the terms:
-24 + 2x + x2 = 16 + -16 + -4x + 4x

Combine like terms: 16 + -16 = 0
-24 + 2x + x2 = 0 + -4x + 4x
-24 + 2x + x2 = -4x + 4x

Combine like terms: -4x + 4x = 0
-24 + 2x + x2 = 0

Factor a trinomial.
(-6 + -1x)(4 + -1x) = 0

Subproblem 1

Set the factor '(-6 + -1x)' equal to zero and attempt to solve: Simplifying -6 + -1x = 0 Solving -6 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1x = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1x = 0 + 6 -1x = 0 + 6 Combine like terms: 0 + 6 = 6 -1x = 6 Divide each side by '-1'. x = -6 Simplifying x = -6

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Solution

x = {-6, 4}

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