(x-335)+(x)(80+2x)=2425

Solution for (x-335)+(x)(80+2x)=2425 equation:

(x-335)+(x)(80+2x)=2425

We move all terms to the left:

(x-335)+(x)(80+2x)-(2425)=0

We add all the numbers together, and all the variables

(x-335)+x(2x+80)-2425=0

We multiply parentheses

2x^2+(x-335)+80x-2425=0

We get rid of parentheses

2x^2+x+80x-335-2425=0

We add all the numbers together, and all the variables

2x^2+81x-2760=0

a = 2; b = 81; c = -2760;
Δ = b2-4ac
Δ = 812-4·2·(-2760)
Δ = 28641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-\sqrt{28641}}{2*2}=\frac{-81-\sqrt{28641}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+\sqrt{28641}}{2*2}=\frac{-81+\sqrt{28641}}{4}
$