(x-3)x=270

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Solution for (x-3)x=270 equation:



(x-3)x=270
We move all terms to the left:
(x-3)x-(270)=0
We multiply parentheses
x^2-3x-270=0
a = 1; b = -3; c = -270;
Δ = b2-4ac
Δ = -32-4·1·(-270)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-33}{2*1}=\frac{-30}{2} =-15 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+33}{2*1}=\frac{36}{2} =18 $

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