(x-3)=2(3x-2)

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Solution for (x-3)=2(3x-2) equation:



(x-3)=2(3x-2)
We move all terms to the left:
(x-3)-(2(3x-2))=0
We get rid of parentheses
x-(2(3x-2))-3=0
We calculate terms in parentheses: -(2(3x-2)), so:
2(3x-2)
We multiply parentheses
6x-4
Back to the equation:
-(6x-4)
We get rid of parentheses
x-6x+4-3=0
We add all the numbers together, and all the variables
-5x+1=0
We move all terms containing x to the left, all other terms to the right
-5x=-1
x=-1/-5
x=1/5

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