(x-3)2=(x-1)(x-2)

Solution for (x-3)2=(x-1)(x-2) equation:

(x-3)2=(x-1)(x-2)

We move all terms to the left:

(x-3)2-((x-1)(x-2))=0

We multiply parentheses

2x-((x-1)(x-2))-6=0

We multiply parentheses ..

-((+x^2-2x-1x+2))+2x-6=0


We calculate terms in parentheses: -((+x^2-2x-1x+2)), so:

(+x^2-2x-1x+2)

We get rid of parentheses

x^2-2x-1x+2

We add all the numbers together, and all the variables

x^2-3x+2

Back to the equation:

-(x^2-3x+2)


We add all the numbers together, and all the variables

2x-(x^2-3x+2)-6=0

We get rid of parentheses

-x^2+2x+3x-2-6=0

We add all the numbers together, and all the variables

-1x^2+5x-8=0

a = -1; b = 5; c = -8;
Δ = b2-4ac
Δ = 52-4·(-1)·(-8)
Δ = -7
Delta is less than zero, so there is no solution for the equation