(x-3)/6=2-x

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Solution for (x-3)/6=2-x equation:



(x-3)/6=2-x
We move all terms to the left:
(x-3)/6-(2-x)=0
We add all the numbers together, and all the variables
(x-3)/6-(-1x+2)=0
We get rid of parentheses
(x-3)/6+1x-2=0
We multiply all the terms by the denominator
(x-3)+1x*6-2*6=0
We add all the numbers together, and all the variables
(x-3)+1x*6-12=0
Wy multiply elements
(x-3)+6x-12=0
We get rid of parentheses
x+6x-3-12=0
We add all the numbers together, and all the variables
7x-15=0
We move all terms containing x to the left, all other terms to the right
7x=15
x=15/7
x=2+1/7

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