(x-3)/3=(3x-5)/2

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Solution for (x-3)/3=(3x-5)/2 equation: 



(x-3)/3=(3x-5)/2

We move all terms to the left:

(x-3)/3-((3x-5)/2)=0

We calculate fractions


x/()+(-((3x-5)*3)/()=0



We calculate terms in parentheses: +(-((3x-5)*3)/(), so:

-((3x-5)*3)/(

We multiply all the terms by the denominator


-((3x-5)*3)



We calculate terms in parentheses: -((3x-5)*3), so:

(3x-5)*3

We multiply parentheses

9x-15

Back to the equation:

-(9x-15)



We get rid of parentheses

-9x+15

Back to the equation:

+(-9x+15)



We get rid of parentheses

x/()-9x+15=0

We multiply all the terms by the denominator


x-9x*()+15*()=0

We add all the numbers together, and all the variables

x-9x*()=0

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