(x-3)/2x=(x-5)/x

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Solution for (x-3)/2x=(x-5)/x equation: 



(x-3)/2x=(x-5)/x

We move all terms to the left:

(x-3)/2x-((x-5)/x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(x-3)*x)/2x^2+(-((x-5)*2x)/2x^2=0

We calculate fractions


((x-3)*x)*2x^2)/(2x^2+(*2x^2)+(-((x-5)*2x)*2x^2)/(2x^2+(*2x^2)=0



We calculate terms in parentheses: +(-((x-5)*2x)*2x^2)/(2x^2+(*2x^2), so:

-((x-5)*2x)*2x^2)/(2x^2+(*2x^2

We multiply all the terms by the denominator


-((x-5)*2x)*2x^2)+((*2x^2)*(2x^2

Back to the equation:

+(-((x-5)*2x)*2x^2)+((*2x^2)*(2x^2)



We get rid of parentheses

((x-3)*x)*2x^2)/(2x^2+*2x^2+(-((x-5)*2x)*2x^2)+((*2x^2)*2x^2=0

We multiply all the terms by the denominator


((x-3)*x)*2x^2)+(*2x^2)*(2x^2+((-((x-5)*2x)*2x^2))*(2x^2+(((*2x^2)*2x^2)*(2x^2=0

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