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(x-3)/(x+3)+(5)/(x+3)+5=0
Domain of the equation: (x+3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(x-3)+5*(x+3)+5=0
We multiply parentheses
(x-3)+5x+15+5=0
We get rid of parentheses
x+5x-3+15+5=0
We add all the numbers together, and all the variables
6x+17=0
We move all terms containing x to the left, all other terms to the right
6x=-17
x=-17/6
x=-2+5/6
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