(x-3)+(x+-5)=30-x-(x-2)

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Solution for (x-3)+(x+-5)=30-x-(x-2) equation: 



(x-3)+(x+-5)=30-x-(x-2)

We move all terms to the left:

(x-3)+(x+-5)-(30-x-(x-2))=0

We add all the numbers together, and all the variables

(x-3)+(x-5)-(30-x-(x-2))=0

We get rid of parentheses

x+x-(30-x-(x-2))-3-5=0



We calculate terms in parentheses: -(30-x-(x-2)), so:

30-x-(x-2)

determiningTheFunctionDomain
-x-(x-2)+30

We add all the numbers together, and all the variables

-1x-(x-2)+30

We get rid of parentheses

-1x-x+2+30

We add all the numbers together, and all the variables

-2x+32

Back to the equation:

-(-2x+32)



We add all the numbers together, and all the variables

2x-(-2x+32)-8=0

We get rid of parentheses

2x+2x-32-8=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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