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(x-3)(x-5)=11-4x
We move all terms to the left:
(x-3)(x-5)-(11-4x)=0
We add all the numbers together, and all the variables
(x-3)(x-5)-(-4x+11)=0
We get rid of parentheses
(x-3)(x-5)+4x-11=0
We multiply parentheses ..
(+x^2-5x-3x+15)+4x-11=0
We get rid of parentheses
x^2-5x-3x+4x+15-11=0
We add all the numbers together, and all the variables
x^2-4x+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{2}=2$
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